45m^2-320=0

Solution for 45m^2-320=0 equation:

45m^2-320=0

a = 45; b = 0; c = -320;
Δ = b2-4ac
Δ = 02-4·45·(-320)
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-240}{2*45}=\frac{-240}{90}
=-2+2/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+240}{2*45}=\frac{240}{90}
=2+2/3
$